백준

[1546] 평균

Jcoder 2018. 5. 14. 22:11



#include <stdio.h>
int main()
{
int max = 0, a[1000] = { 0, }, i, n;
double sum = 0;
scanf("%d", &n);
for (i = 0; i < n; i++)
{
scanf("%d", &a[i]);
max < a[i] ? (max = a[i]) : max;
}
for (i = 0; i < n; i++)
sum += (double)a[i] / (double)max * 100.0;
printf("%.2lf", sum / (double)n);
return 0;
}